send variables to another page

[tau9]

Hi,

I'm stuck on sending variables to another page and then printing them can someone have a look at the code for me please.

This is on page 1:
the form goes like this

<input name="user" type="text" id="user" value=<?php $user?>>

This then runs a script that checks if the user is registered and then he/she is verified.

$user=$_POST['user'];

I want to post the to the 2nd page via

header("location:secondpage.php") and also the other pages in the members area. The user name should be printed out and posted.

I have tried header("location:secondpage.php?".$Post['user']:"");

Tried echo to print the user in the second page but doesn't seem to work any ideas.

thanks in advance

[abduraooft]

<input name="user" type="text" id="user" value=<?php $user?>>

should be

<input name="user" type="text" id="user" value=<?php echo  $user ;?>>

.

However, you'd need to use sessions to effectively pass such informations. See http://php.net/session_start

[tau9]

Thanks for the reply

I have a session created but I thought that if I wanted send variables I would send them through the header.

session_start();
$_SESSION["logged"]=1;

I'm sorry I'm a newbie I still don't see how to send the user name

I have tried but no joy any idea what i'm doing wrong.

if(!isset($_SESSION['user']));

thanks in advance

[abduraooft]

Have you tried the example given in the above manual page?

[tau9]

Yes I've tried the above manual but I think the way I am verifiying the user might be the problem. As I'm starting the session and the creating a session id I don't name it anything just give it a value of 1.

What do you think?

<?php
if($count==1){
//Register $user, $password and redirect to file "login_success.php"
session_register("user");
session_register("password");
session_start();
$_SESSION["logged"]=1;

header("location:login_success.php");
}
else {
$_SESSION["logged"]=0;
//echo "Wrong User ID or Password";
}

thanks in advance

[timgolding]

Yes I've tried the above manual but I think the way I am verifiying the user might be the problem. As I'm starting the session and the creating a session id I don't name it anything just give it a value of 1.

What do you think?

<?php
if($count==1){
//Register $user, $password and redirect to file "login_success.php"
session_register("user");
session_register("password");
session_start();
$_SESSION["logged"]=1;

header("location:login_success.php");
}
else {
$_SESSION["logged"]=0;
//echo "Wrong User ID or Password";
}

thanks in advance

As quoted on php.net

Caution

If you are using $_SESSION (or $HTTP_SESSION_VARS), do not use session_register(), session_is_registered(), and session_unregister().

You don't need those session_register functions. you should remove them and then set the session vars after session_start like so

session_start();
$_SESSION["logged"]=1;
$_SESSION["username"] = $user;
$_SESSION["password"] = $password; 

Just out of curiosity is it necessary to store the user password?

[tau9]

no I dont need to store the password so I am going to leave it out
thanks


I have used the code below and found that the session remains open and the number is incremented but how can the user name be posted on the page.

I am trying to get something like this: User: Dave viewed:20 times

I have tried the manual above but no luck any ideas.

<?php
if(isset($_SESSION['user'])) $_SESSION['user']=$_SESSION['user']+1;
else $_SESSION['user']=1;echo "=". $_SESSION['user'];

?>


Sorry thats wrong I need to post the username to the nextpage the counter allows me to keep track of the viewed pages.
thanks in advance.

[timgolding]

I guess you will need two session variables. However if i was keeping count of how many views a person has done I would store it more permanently. Probably with a MySQL database or something. Anyway. Here is the code for the sessions.

<?php
session_start();
if(isset($_SESSION['user'])) $_SESSION['counter']++;
else 
{
$_SESSION['counter']=1;
$_SESSION['user']=$user;
}
echo "=". $_SESSION['user'] . "viwed: " . $_SESSION['counter'] . " times";
?>