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  • Problem with "distinct"

    SELECT DISTINCT
    a.field1, c.field2, a.field3, left(d.field4,15)
    FROM tbl_Table1 a
    LEFT JOIN tbl_Table2_R c ON a.field1 = c.FKField1
    LEFT JOIN tbl_Table3_R d ON a.Field1= d.FKField1
    WHERE 1=1
    AND a.field3= 'text' ORDER BY a.field3


    is returning duplicate a.field1 values where there are many d.field4s for the 1 a.field1. I'm totally stumped as i need it to return only 1 record per a.field1... I'm running SQL server 7.0

    thanks in advance.

  • #2
    SELECT DISTINCT
    a.field1, c.field2, a.field3, left(d.field4,15)
    FROM tbl_Table1 a
    LEFT JOIN tbl_Table2_R c ON a.field1 = c.FKField1
    LEFT JOIN tbl_Table3_R d ON a.Field1= d.FKField1
    WHERE 1=1
    AND a.field3= 'text' ORDER BY a.field3, a.field1

    Same problem

    any more ideas?

    Comment


    • #3
      GOT IT!!

      Ok guys... if anyone else has the same problem... after much thinking, i came up with a cheater way to accompish what i wanted!!

      here is the solution!

      SELECT DISTINCT
      a.field1, c.field2, a.field3, MAX(left(d.field4,15))
      FROM tbl_Table1 a
      LEFT JOIN tbl_Table2_R c ON a.field1 = c.FKField1
      LEFT JOIN tbl_Table3_R d ON a.Field1= d.FKField1
      WHERE 1=1
      AND a.field3= 'text' GROUP BY a.field3, a.field1, c.field3

      Just add max to all the fields that might be Many -> 1 with your primary table.

      Comment


      • #4
        Let me splain

        Just so you know, distinct selects distinct rows, not a distinct column. Thus, select distinct col1, col2 from x will give you all distinct rows. If col1 = x 100 times but col2 = x+1 within each row, you will get 100 rows in your result set.

        Peace, Love, and Darth Vader.

        Comment

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