Preface: yes this is a homework assignment but I've already done it and there's one "bug" that seems to be keeping me down... I have a PHP background so some of C's quirks really gets me sometimes...
Anywho this program compiles and runs correctly but it seems to skip the third scanf() call (the one that asks to input a character) and instead skips to the output. Here's the code and an example execution:
Sample execution:
What's the deal with it skipping the third scanf? Thanks!
Anywho this program compiles and runs correctly but it seems to skip the third scanf() call (the one that asks to input a character) and instead skips to the output. Here's the code and an example execution:
Code:
#include <stdio.h> int main(void){ // declare variables double doub1, doub2, doub3, sum; int integer1; char char1; // input the numbers printf("Enter 3 numbers with decimals: "); scanf("%f%f%f", &doub1, &doub2, &doub3); printf("\nNow enter an integer: "); scanf("%d", &integer1); printf("\nFinally, enter a single character: "); scanf("%c", &char1); // output 3 doubles as floats printf("\n\nDoubles as Floats:\n%6.2f\n%6.2f\n%6.2f", doub1, doub2, doub3); // output integer printf("\n\nInteger with padded zeros:\n%06d", integer1); // output character printf("\n\nInputted character \"%c\" as number:\n%d", char1, char1); // add and print final value sum = doub1 + doub2 + doub3 + integer1 + char1; printf("\n\nSum of values:\n%8.2f\n\n", sum); return 0; }
Code:
Enter 3 numbers with decimals: 2.325 1.256 1.445 Now enter an integer: 5 Finally, enter a single character: Doubles as Floats: -92559604392960731000000000000000000000000000000000000000000000.00 -92559604306135282000000000000000000000000000000000000000000000.00 -92559604324237887000000000000000000000000000000000000000000000.00 Integer with padded zeros: 000005 Inputted character " " as number: 10 Sum of values: -277678813023333900000000000000000000000000000000000000000000000.00 Press any key to continue . . .
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