Why is this simple C program skipping a scanf?

[coasters2k]

Preface: yes this is a homework assignment but I've already done it and there's one "bug" that seems to be keeping me down... I have a PHP background so some of C's quirks really gets me sometimes...

Anywho this program compiles and runs correctly but it seems to skip the third scanf() call (the one that asks to input a character) and instead skips to the output. Here's the code and an example execution:

#include <stdio.h>

int main(void){
	// declare variables
	double doub1, doub2, doub3, sum;
	int integer1;
	char char1;

	// input the numbers
	printf("Enter 3 numbers with decimals: ");
	scanf("%f%f%f", &doub1, &doub2, &doub3);
	printf("\nNow enter an integer: ");
	scanf("%d", &integer1);
	printf("\nFinally, enter a single character: ");
	scanf("%c", &char1);

	// output 3 doubles as floats
	printf("\n\nDoubles as Floats:\n%6.2f\n%6.2f\n%6.2f", doub1, doub2, doub3);

	// output integer
	printf("\n\nInteger with padded zeros:\n%06d", integer1);

	// output character
	printf("\n\nInputted character \"%c\" as number:\n%d", char1, char1);
	
	// add and print final value
	sum = doub1 + doub2 + doub3 + integer1 + char1;
	printf("\n\nSum of values:\n%8.2f\n\n", sum);

	return 0;
}

Sample execution:

Enter 3 numbers with decimals: 2.325
1.256
1.445

Now enter an integer: 5

Finally, enter a single character:

Doubles as Floats:
-92559604392960731000000000000000000000000000000000000000000000.00
-92559604306135282000000000000000000000000000000000000000000000.00
-92559604324237887000000000000000000000000000000000000000000000.00

Integer with padded zeros:
000005

Inputted character "
" as number:
10

Sum of values:
-277678813023333900000000000000000000000000000000000000000000000.00

Press any key to continue . . .

What's the deal with it skipping the third scanf? Thanks!

[_Aerospace_Eng_]

Use %s instead of %c.

[coasters2k]

Nevermind, I found the problem. I needed to flush the input stream character by putting a space before the "%x" in the two scanfs after the initial one.