Split function in javascript?

[Fou-Lu]

I'm having some troubles with it, and not sure exactly how it works, since I just got a little code off of another site. Anyway, this is what I have, but whenever it trys to execute the function, it always fails:

function myfunction(id,linker){
if (linker){
  arrlinker = split(linker,"|");
for(i=0; i<UBound(arrlinker); i++){
    if(arrlinker(i) == '50'){
            nullFunction();
         }
   }
}

All functions work fine, except when there is a linker. There is also far more too it, but I don't really want to add more details than nessessary. Anyway, if I just have one value in the linker, and instead use if(linker == '50'){nullFunction();} it will work fine, but for some reason this won't. Can anyone explain how the split function correctly works? Thanx!

[A1ien51]

A mistake I see

arrlinker[i] == '50'){

and I do not think Javascript uses UBound since that is VBScript....

You can just use arrlinker.length

[Fou-Lu]

Originally posted by A1ien51
A mistake I see

arrlinker[i] == '50'){

and I do not think Javascript uses UBound since that is VBScript....

You can just use arrlinker.length

Thanx, I finally got that figured out, I just decided to make it more resembling that of what I'm used to and it worked fine.
Another quick question though, can you call a function within itself?
As in:
function myfunction(bunch'ostuff){
if(bunch'ostuff == 'x'){
myfunction(lessbunch'ostuff);
}
}
Will that cause it to continue the original function after completing the one inside?

[Basscyst]

Yes it will do just that.

Basscyst