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**Willy Duitt** · Feb 8, 2004, 04:25 PM

I'm still struggling with regular expressions myself.
So forgive me if there is a better way.

string.search(/^[\-+0-9+\.]*$/);

.....Willy

**homerUK** · Feb 8, 2004, 04:42 PM

hey thanks for the fast response...
i tried

if ((ignoreWhiteSpace && string.search(/^[\-+0-9+\.]*$/) != -1) || (!ignoreWhiteSpace && string.search(/\D/) != -1))

but it still didnt seem to work... it wouldnt allow a "."

not really sure what I am doing!!

**Willy Duitt** · Feb 8, 2004, 05:26 PM

As I said, I'm still struggling.
But I think you are missing either the .match or .test methods.

Here is an example of how I would use it:

Code:

<script type="text/javascript">
function isNumber(field){
  var regex = /^[\-+0-9+\.]*$/;
   if (!regex.test(field.value)){
       field.value = field.value.replace(/[^\-+0-9+\.]/g,"");
   }
 }

</script>
</head>

<body>
<form name="form1">
<input type="text" name="firstnumber" onkeyup="isNumber(this)">
</form>

Perhaps someone who actually knows regex will soon
come along and straighten us both out. Until then....

Hope this is of some help;
.....Willy

**Jeff Mott** · Feb 8, 2004, 05:34 PM

Code:

[size=2]if (/[^\d.-]/.test(string))
    ; /* bad */
else
    ; /*good */[/size]

Though note that matching this pattern does not mean the string is a number (e.g., "-.-.-" is not a number). Instead use the isNaN function.

Code:

[size=2]if (isNaN(string))
    ; /* not a number */
else
    ; /* a number */[/size]

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