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  • #1

    regular expression help

    Hi,

    I have a regular expression that is searched on a field coming from a form....

    It basically returns true or false and looks for ONLY numbers.. ie: It validates that the entry is only numbers, and nothing else.

    I need it changing so that it will allow a period (.) and a minus (-)

    here's what I have at the mo

    string.search(/[^\d\s]/)

    how do I make it so that only numbers, a full stop and a minus can be entered??

    thanks for any help
    www.mattfacer.com
    Tags: None
  • #2
    I'm still struggling with regular expressions myself.
    So forgive me if there is a better way.

    string.search(/^[\-+0-9+\.]*$/);

    .....Willy

    Comment

    • #3
      hey thanks for the fast response...
      i tried

      if ((ignoreWhiteSpace && string.search(/^[\-+0-9+\.]*$/) != -1) || (!ignoreWhiteSpace && string.search(/\D/) != -1))

      but it still didnt seem to work... it wouldnt allow a "."

      not really sure what I am doing!!
      www.mattfacer.com

      Comment

      • #4
        As I said, I'm still struggling.
        But I think you are missing either the .match or .test methods.

        Here is an example of how I would use it:
        Code:
        <script type="text/javascript">
function isNumber(field){
  var regex = /^[\-+0-9+\.]*$/;
   if (!regex.test(field.value)){
       field.value = field.value.replace(/[^\-+0-9+\.]/g,"");
   }
 }

</script>
</head>

<body>
<form name="form1">
<input type="text" name="firstnumber" onkeyup="isNumber(this)">
</form>
        Perhaps someone who actually knows regex will soon
        come along and straighten us both out. Until then....

        Hope this is of some help;
        .....Willy

        Comment

        • #5
          Code:
          [size=2]if (/[^\d.-]/.test(string))
    ; /* bad */
else
    ; /*good */[/size]
          Though note that matching this pattern does not mean the string is a number (e.g., "-.-.-" is not a number). Instead use the isNaN function.
          Code:
          [size=2]if (isNaN(string))
    ; /* not a number */
else
    ; /* a number */[/size]

          Comment

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