Hi people,

I have found this script for validating an email address entered into a form field.

Yet it seems in complete. When you enter e.g. "[email protected]". It works. But when you put "[email protected]" it still works. So it needs a bit adding to it. In the script it checks to make sure there are characters after the '.', but it needs a section to check that there are characters before the '.' also. I have tried figuring it out, but to no evail. Any one help me with this little addition.

Thanks in advance

oops, forgot the code the first time round when posting, here it is !!!!!

function validEmail(email) {

invalidChars = " /:,;"

if (email == "") { // Cannot be empty

return false

}

for (i=0; i<invalidChars.length; i++) { // Does it contain any invalid characters

badChar = invalidChars.charAt(i)

if (email.indexOf(badChar,0) > -1) {

return false

}

}

atPos = email.indexOf("@",1) // There must be at least one '@' symbol

if (atPos == -1) {

return false

}

if (email.indexOf("@",atPos+1) != -1) { // And only one '@' symbol

return false

}

periodPos = email.indexOf(".",atPos) // at least one '.' after the '@'

if (periodPos == -1) {

return false

}

if (periodPos+3 > email.length) { // must be at least 2 characters after the '.'

return false

}

return true

}

I have found this script for validating an email address entered into a form field.

Yet it seems in complete. When you enter e.g. "[email protected]". It works. But when you put "[email protected]" it still works. So it needs a bit adding to it. In the script it checks to make sure there are characters after the '.', but it needs a section to check that there are characters before the '.' also. I have tried figuring it out, but to no evail. Any one help me with this little addition.

Thanks in advance

oops, forgot the code the first time round when posting, here it is !!!!!

function validEmail(email) {

invalidChars = " /:,;"

if (email == "") { // Cannot be empty

return false

}

for (i=0; i<invalidChars.length; i++) { // Does it contain any invalid characters

badChar = invalidChars.charAt(i)

if (email.indexOf(badChar,0) > -1) {

return false

}

}

atPos = email.indexOf("@",1) // There must be at least one '@' symbol

if (atPos == -1) {

return false

}

if (email.indexOf("@",atPos+1) != -1) { // And only one '@' symbol

return false

}

periodPos = email.indexOf(".",atPos) // at least one '.' after the '@'

if (periodPos == -1) {

return false

}

if (periodPos+3 > email.length) { // must be at least 2 characters after the '.'

return false

}

return true

}

## Comment