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**Vladdy** · Jul 9, 2002, 02:03 PM

x = new Array('foo1()'.'foo2()'.'foo3()');

//call foo1()
eval(x[0]);

//call foo2()
eval(x[1]);

//rinse ... repeat

**Soldier Bob** · Jul 9, 2002, 02:05 PM

how do you mean?

I believe I understand the programming structure you want to make.

But let me just clarify.

Do you mean place the names of the functions into an array so that a function can be called by an array lookup?

or do you mean placing the whole function into an array for something like a retrival system?

if I remember correctly you can cobble together statements from variables that call functions.
so that you could call func01 -func10, If those were the names of the functions by adding the suffix 'i'. if 'i' was a counter in a loop.

---PSEUDO CODE---
for (i=1;i<11;i++) {
eval('func' + i + '()');
}
---PSEUDO CODE---

something like that (I didnt test this yet)

what exactly are you doing with the functions?

-S Bob.

**ASAAKI** · Jul 9, 2002, 02:08 PM

maybe this'll work

for(var i=0;i<3;i++){
x[i]="foo"+i+"()";
}

it should get x to store the names of the three funtions.

**adios** · Jul 9, 2002, 05:45 PM

<html>
<head>
<title>untitled</title>
<script type="text/javascript" language="JavaScript">

function foo0() {alert('foo0')}
function foo1() {alert('foo1')}
function foo2() {alert('foo2')}

var x = new Array(foo0, foo1, foo2);

x[0]();
x[1]();
x[2]();

</script>
</head>
<body>
</body>
</html>

Announcement

how to fill array with functions?

how to fill array with functions?

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